k^2-16k-86=-6

Solution for k^2-16k-86=-6 equation:

k^2-16k-86=-6

We move all terms to the left:

k^2-16k-86-(-6)=0

We add all the numbers together, and all the variables

k^2-16k-80=0

a = 1; b = -16; c = -80;
Δ = b2-4ac
Δ = -162-4·1·(-80)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*1}=\frac{-8}{2}
=-4
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*1}=\frac{40}{2}
=20
$